if 2x^2+6x+b is a quadratic equation, where b is less than zero. the the value of alpha/beta + beta/alphs is less than

i assume alpha and beta are roots of above equation

sum of roots = -3
Product of roots= b/2


=
=
= (18-b)/b = 18/b -1
Since b is less than 0 first term will be negative
So maximum value of above will be -1.

Yes i miss that part
Answer will be -2
At this step
= [(9-2(b/2))/b/2]
= (18-2b)/b = 18/b -2
Since b is less than 0 first term will be negative
So maximum value of above will be -2.