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If 2 + i √3 is a root of the equation x2 + px + q = -, where p and q are real, then (p, q) = (. . . . . . . . .).

If 2 + i √3 is a root of the equation x2 + px + q = -, where p and q are real, then (p, q) = (. . . . . . . . .).

Grade:11

1 Answers

Kevin Nash
askIITians Faculty 332 Points
9 years ago
As p and q are real and one root is 2 + i √3, other should be 2 – i √3
Then p = - (sum of roots) = -4,
q = product of roots = 4 + 3 = 7

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