 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        If(1+x+x^2)^8=a0+a1x+.....+a16x^16 then a1-a3+a5-a7+.......-a15=`
3 months ago

```							hello oleti. this is an ez application of complex nos:given that (1+x+x^2)^8=a0+a1x+.....+a16x^16multiply both sides by xx(1+x+x^2)^8=a0x+a1x^2+a2x^3+a3x^4.....+a16x^17now, in this identity, put x= iotai(1+i+i^2)^8= a0*i – a1 – a2*i + a3+a4*i – …......+a16i.......(1)now put x= – iota – i(1 – i+i^2)^8= – a0*i – a1+a2*i+a3 – a4*i – …........ – a16i......(2)add (1) and (2)i(1+i+i^2)^8 – i(1 – i+i^2)^8= – 2(a1 – a3 + a5 – …....... – a15)or i*i^8 – i*i^8= – 2(a1 – a3 + a5 – …....... – a15)0= – 2(a1 – a3 + a5 – …....... – a15)or a1-a3+a5-a7+.......-a15= 0kindly approve :)
```
3 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions