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```
if 1/x^2-25=1/k[1/x-5-1/x+5] then find the value of k

```
10 months ago

Arun
25384 Points
```							Dear student Pleas ask question properly as it is not clear where bracket is used and which term is in numerator and denominator. Please attach an image if possible. I will be happy to help you
```
10 months ago
2069 Points
```							hello mrinal, the ques can simply be solved as follows:1/(x^2-25) = 1/k[1/(x-5) – 1/(x+5)] or 1/(x^2-25) = 1/k[{(x+5) – (x – 5)}/(x-5)(x+5)]or 1/(x^2-25) = 1/k[10/(x^2-25)]or k = 10kindly approve :))
```
10 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions