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Grade: 8

                        

if 1/x^2-25=1/k[1/x-5-1/x+5] then find the value of k

10 months ago

Answers : (2)

Arun
25384 Points
							
Dear student
 
Pleas ask question properly as it is not clear where bracket is used and which term is in numerator and denominator. Please attach an image if possible.
 
I will be happy to help you
10 months ago
Aditya Gupta
2069 Points
							
hello mrinal, the ques can simply be solved as follows:
1/(x^2-25) = 1/k[1/(x-5) – 1/(x+5)] 
or 1/(x^2-25) = 1/k[{(x+5) – (x – 5)}/(x-5)(x+5)]
or 1/(x^2-25) = 1/k[10/(x^2-25)]
or k = 10
kindly approve :))
10 months ago
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