if 1/x^2-25=1/k[1/x-5-1/x+5] then find the value of k
mrinal , 5 Years ago
Grade 8
2 Answers
Arun
Last Activity: 5 Years ago
Dear student
Pleas ask question properly as it is not clear where bracket is used and which term is in numerator and denominator. Please attach an image if possible.
I will be happy to help you
Aditya Gupta
Last Activity: 5 Years ago
hello mrinal, the ques can simply be solved as follows:
1/(x^2-25) = 1/k[1/(x-5) – 1/(x+5)]
or 1/(x^2-25) = 1/k[{(x+5) – (x – 5)}/(x-5)(x+5)]
or 1/(x^2-25) = 1/k[10/(x^2-25)]
or k = 10
kindly approve :))
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