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`        If 1.(0!) + 3(1!) + 7(2!) + 13(3!) + 21(4!)+... upto n terms = (4000)4000!, then n is equal to ????`
2 years ago

Arun
23381 Points
```							Dear student Remember thatSigma[k! [(k+1)(k+2) - 2(k+1) + 1 ] = (k+1) [(k+1)! ] Hence in the above question k = 3999 RegardsArun (askIITisns forum expert)
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions