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I know that log x^2= 2logx . But it log2^2 /1 = 2log2/1 then why not 2log 2/1^2 ??????

I know that log x^2= 2logx   .       But it log2^2 /1 = 2log2/1 then why not 2log 2/1^2   ??????
 

Grade:12

1 Answers

Anish Singhal
askIITians Faculty 1192 Points
5 years ago
Use property log m^n= n log m.

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