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I have posted this question 5 times and still no reply. These IITians cant solve simple polynomial questions. Please show that you are IITians Q.1-> a^2=b+c b^2=c+a c^2=a+b find (1/a+1)+(1/b+1)+(1/c+1) Q.2-> If (1/b+c) +(1/c+a)=(2/a+b) find a^2+b^2 please give the solution.

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6 years ago bharat bajaj
IIT Delhi
122 Points
```							Sorry for the delay,Subtract equation 1 from 2 :a^2 - b^2 = b - a(a+b) (a-b) = b-aHence, a + b = -1Similarly,b+c = -1c+a = -1a+b = -1Now subtract any two derived equations :b - a = 0, c - b = 0, a - c = 0Hence, a = b = c = -1/2Hence, now the given equation = 3/a+1 = 6Answer = 6Q2 : Take LCM ,(2c+a+b)/(a+c)(b+c) = 2/a+bCross multiply:a^2 + b^2 + 2ab + 2bc + 2ac = 2bc + 2ab + 2c^2 + 2acThis gives,a^2 + b^2 = 2. c^2ThanksBharat Bajajaskiitians facultyIIT Delhi
```
6 years ago bharat bajaj
IIT Delhi
122 Points
```							Q1.Subtract equation 1 from 2 :a^2 - b^2 = b - a(a+b) (a-b) = b-aHence, a + b = -1Similarly,b+c = -1c+a = -1a+b = -1Now subtract any two derived equations :b - a = 0, c - b = 0, a - c = 0Hence, a = b = c = -1/2Hence, now the given equation = 3/a+1 = 6Answer = 6Q2 : Take LCM ,(2c+a+b)/(a+c)(b+c) = 2/a+bCross multiply:a^2 + b^2 + 2ab + 2bc + 2ac = 2bc + 2ab + 2c^2 + 2acThis gives,a^2 + b^2 = 2. c^2ThanksBharat Bajajaskiitians facultyIIT Delhi
```
6 years ago
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