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`        I am getting problem in solving this question .please!! solve this. `
29 days ago

1670 Points
```							2^x*5^y= 1 and 5^(x+1)= 2^(1 – y)we take log base 10 both sides for both eqns and use properties of logarithmslog(2^x*5^y)= log(1)= 0 or log2^x + log5^y= 0 or xlog2 + ylog5= 0....(1)and log(5^(x+1))= log(2^(1 – y)) or (x+1)log5= (1 – y)log2......(2)solving (1) and (2) for x and y, we gety= log2/(log2+log5)= log2/log(2*5)= log2/log10= log2/1= log2and x= – log5/(log2+log5)= – log5/log10= – log5/1= log(1/5)so option C is correctkindly approve :)
```
29 days ago
Vikas TU
8732 Points
```							Dear student Here you need to go by alternate method , You need to check by option ,Log 2 = 0.301Log 5 = 0.69 Put the options a, b , c , d in the question 2^x * 5^y = 15^(x+1) * 2^y = 1Option c is correct ans.
```
29 days ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions