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Grade: 12th pass
        
How To Solve These type of equations...
  (9x2-3x-2)(x2-3x+2)=21.
what is the Value(s) of “x”??
 
3 years ago

Answers : (3)

Harsh Patodia
IIT Roorkee
askIITians Faculty
906 Points
							PFA
228-760_7.PNG

Otherwise u can form biquadratic and take 21 on other side and try factorizing using hit and trial.
3 years ago
Kuldeep Pal
53 Points
							
But ,I also want to know how many of the roots are irrational or rational.
How  I can judje this on number line.
3 years ago
mycroft holmes
272 Points
							
Write the equation as (3x+1)(3x-2)(x-1)(x-2) = 21
 
Club the 2nd and 3rd factors, and 1st and 4th factor to get
 
(3x2-5x+2)(3x2-5x+2) = 21 or (3x2-5x)2 – 4 = 21 from which
 
3x2-5x = 5 or 3x2-5x = -5. i.e.
3x2-5x-5 = 0 or 3x2-5x+5 = 0 and now you are good to go.
3 years ago
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