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How to find the equation of line points (1,2,3),(-1,2,3)

msd k , 6 Years ago
Grade 11
anser 1 Answers
venkat

Last Activity: 6 Years ago

The answer is very simple.
First,find the d.r’s of the given line
i.e.,  d.r’s of the line (a,b,c) = (-2,0,0)
Now the equation of line is given by
             
            (x-x1)/a=(y-y1)/b=(z-z1)/c
Since the line passes through the point  (1,2,3), treat them as (x1,y1,z1)
So,the equation of the line is
    (x-1)/(-2)=(y-2)/0=(z-3)/0
      In terms of vector eqation it can be written as 
          \vec{r}=(1-t)\vec{a}+t\vec{b}
where \vec{a}&\vec{b} are the position vectors of the given points

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