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how many solutions are there of (n^2-n)C2= (n^2-n)C10

how many solutions are there of (n^2-n)C2= (n^2-n)C10
 

Grade:11

1 Answers

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137 Points
6 years ago
There are 2 solutions nCr=nC(n-r) so by this we can say that n^2 - n -12=0 this gives (n=4) and (n=-3).

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