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Grade: 11
        
How many nine digit numbers can be formed using the digits: 2, 2, 3, 3, 5, 5, 8, 8, 8 so that odd digits occupy even positions?
10 months ago

Answers : (2)

Arun
22572 Points
							

There are only 6 distinct ways the numbers 3355 (odd numbers ) can be arranged and there are 10 distinct ways the numbers 22888 (even numbers) can be arranged

So the possible arrangements are 6 x 10 = 60

10 months ago
Yash Patil
33 Points
							
Assume all the digits are distinct.
So , total words = 5!x4!
now, 8 is repeated 3 time while 2,3,5 are repeated 2 times
 
therefore , 5!x4! / 2!x2!x2!x3! = 60
10 months ago
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