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`        How many nine digit numbers can be formed using the digits: 2, 2, 3, 3, 5, 5, 8, 8, 8 so that odd digits occupy even positions?`
one year ago

## Answers : (2)

Arun
24740 Points
```							There are only 6 distinct ways the numbers 3355 (odd numbers ) can be arranged and there are 10 distinct ways the numbers 22888 (even numbers) can be arrangedSo the possible arrangements are 6 x 10 = 60
```
one year ago
Yash Patil
33 Points
```							Assume all the digits are distinct.So , total words = 5!x4!now, 8 is repeated 3 time while 2,3,5 are repeated 2 times therefore , 5!x4! / 2!x2!x2!x3! = 60
```
one year ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions