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How many integers between 999 to 9999 either begin or end with 3 ?
Let A : the set of integers between 999 and 9999 begin with 3Let B : the set of integers between 999 and 9999 ends with 3A = 1 * 103 (begin with 3= 9:1, 9:10, 9:10, 9:10)B = 9 * 10 * 10 * 1 (end with 3= 9:9, 9:10, 9:10, 9:1)AB = 1 *102 *1 (begin and end with 3 9:1, 9:10, 9:10, 9:1)AU B = A + B - AB= 103 + 900 – 100= 1000 + 900 – 100= 18008
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