Aditya Gupta
Last Activity: 5 Years ago
hello khushi. we know that the range of tanx is R.
so keep y=tanx
so now we have to find range of (tanx)2 + tanx= y^2+y
now, when y= ± infinity, y^2+y is + infinity.
now differentiate y^2+y wrt y and equate it to zero to find minimum value.
2y+1=0
or y = – ½
so min value is ¼ – ½
= – ¼
hence the range is [ – ¼, infinity)