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`        HI was heated  in the sealed tube  at 400 degree Celsius still the equilibrium .HIHwas found to be 22% decomposed the equilibriumCONSTANT   of the dissociation is`
one year ago

Arun
23357 Points
```							Dear student  there r 2of eq. constantKc  & Kp             rxn       2HI -> H2 +I2  moles initally   2        0     0moles @eqlb.   2-2x    x      x                                        Kc   =  x*x/{2-2x}^2 = (0.22)^2/4*(0.78)^2 = 0.19888 conc.(C)= P/RT  for gas phase rxn                                           RT *(x)= PH2 = PI2   = 0.19888        (same as   Kc bcz  power o RT cancel out  )
```
one year ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions