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`        Hello sir/madam please give full solution of the both the question with procedure kindly,thankyou `
one year ago

2047 Points
```							let costheta= c and sintheta=snow a+ib=3/(2+c+is)take magnitude both sides and squarea^2+b^2= 9/[(2+c)^2+s^2] = 9/(5+4c)so that a^2+b^2+3= 3(8+4c)/(5+4c)= 6(2+c)/(5+4c)......(1)also, a+ib=3/(2+c+is)= 3(2+c – is)/(5+4c)so a= 3(2+c)/(5+4c)......(2)now dividing (1) by (2)[a^2+b^2+3]/a= 2= lambda option d is correct
```
one year ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions