Given the two valid equations, where a and b are constants,

2ax+4by=−2 and 4ax+16by=4.

Solve for y in terms of b only.
y=

Question

Given the two valid equations, where a and b are constants, 2 ax +4 by = − 2 and 4 ax +16 by =4. Solve for y in terms of b only. y=

Satyam Negi · Answer

According to the question.. 2ax + 4by = -2 4ax + 16by = 4 Multipyling the 1st equation by 2 we get.. 2(2ax + 4by = -2) = 4ax + 8by = -4 Now, subtracting the 1st equation by the 2nd equation, we get... (4ax + 16by = 4) - (4ax + 8by = -4) 4ax + 16by - 4ax - 8by = 4 - (-4) 8by = 8 by=1 y = (1/b)

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Given the two valid equations, where a and b are constants, 2 ax +4 by = − 2 and 4 ax +16 by =4. Solve for y in terms of b only. y=

Given the two valid equations, where a and b are constants,

2ax+4by=−2 and 4ax+16by=4.

Solve for y in terms of b only.
y=

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Given the two valid equations, where a and b are constants, 2 ax +4 by = − 2 and 4 ax +16 by =4. Solve for y in terms of b only. y=

Given the two valid equations, where a and b are constants, 2ax+4by=−2 and 4ax+16by=4. Solve for y in terms of b only.y=

1 Answers

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Given the two valid equations, where a and b are constants,

2ax+4by=−2 and 4ax+16by=4.

Solve for y in terms of b only.
y=