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`        Given the two valid equations, where a and b are constants, 2ax+4by=−2 and 4ax+16by=4. Solve for y in terms of b only.y=`
10 months ago

Satyam Negi
38 Points
```							According to the question.. 2ax + 4by = -24ax + 16by = 4 Multipyling the 1st equation by 2 we get..2(2ax + 4by = -2)= 4ax + 8by = -4 Now, subtracting the 1st equation by the 2nd equation, we get...(4ax + 16by = 4) - (4ax + 8by = -4)4ax + 16by - 4ax - 8by = 4 - (-4)8by = 8by=1y = (1/b)
```
10 months ago
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## COUPON CODE: SELF10

### Course Features

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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions