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Grade: 12th pass
        
Given the two valid equations, where a and b are constants,

 

2ax+4by=and 4ax+16by=4.
 

Solve for y in terms of b only.

y=

5 months ago

Answers : (1)

Satyam Negi
38 Points
							
According to the question..
 
2ax + 4by = -2
4ax + 16by = 4
 
Multipyling the 1st equation by 2 we get..
2(2ax + 4by = -2)
= 4ax + 8by = -4
 
Now, subtracting the 1st equation by the 2nd equation, we get...
(4ax + 16by = 4) - (4ax + 8by = -4)
4ax + 16by - 4ax - 8by = 4 - (-4)
8by = 8
by=1
y = (1/b)
5 months ago
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