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Grade: 12th Pass
        
Given that ax+ bx + c = 0 has no real roots and a + b + c
  1. c = 0
  2. c > 0
  3. c
  4. None of these
4 years ago

Answers : (20)

grenade
2061 Points
							
will u please complete the question
the data is not sufficient
4 years ago
Anjali Singh
23 Points
							
 
Given that ax+ bx + c = 0 has no real roots and a + b + c
  1. A.c = 0
  2. B.c > 0
  3. C.c
  4. D.None of these
  5. This is the question :-)
4 years ago
Anjali Singh
23 Points
							
Given that ax+ bx + c = 0 has no real roots and a + b + c less than 0
4 years ago
Anjali Singh
23 Points
							
Need the answer reallyfast. PLEASE.
4 years ago
grenade
2061 Points
							
what about the third option
4 years ago
grenade
2061 Points
							
just check out that the dicriminant should be less than 0 of the non real roots
4 years ago
grenade
2061 Points
							
b2 −4ac
4 years ago
Anjali Singh
23 Points
							
c less than 0 is the third option
 
I kind of deducted that b2-4ac 2is always positive...so “ac” should also be positive, implying that a and c should bopth either be positive or negative. I don’t know if I am right or not
4 years ago
Anjali Singh
23 Points
							
damn the keyboard. I mean b^2 – 4ac always less than 0 so since b^2 is always positive, ac has to be positive
4 years ago
grenade
2061 Points
							
of course
4 years ago
grenade
2061 Points
							
an example is here
 
-8x2 +4x-1
i think that the example is fullfilling all the conditions of your question just check out
4 years ago
Anjali Singh
23 Points
							
Can you somehow prove it graphically?
4 years ago
grenade
2061 Points
							
over here image cannot be posted be a student
sorry
4 years ago
Anjali Singh
23 Points
							
can you prove it mathematically? Your exapmle fits perfectly but I would really like to know the concept behind the question.
4 years ago
grenade
2061 Points
							
ok let me tell u then
do
u know Descartes' rule of signs
search it out on google or ask your teacher than the problen is direct
nothing to be confusing just check it out
4 years ago
Nicho priyatham
625 Points
							
answer is option c
if a+b+c is less than 0 that means that f(1) is less than  zero 
so  since the given quartatic has no real roots  the whole graph (parabola) lies below x axis 
so f(x)
so c=f(0) is also less than zero
4 years ago
Nicho priyatham
625 Points
							
PLZ APPROVE
 
4 years ago
grenade
2061 Points
							
in your case don’t apply descarets law because this law is for determining the nature of roots of higher degree equations
4 years ago
grenade
2061 Points
							
in your case don’t apply descarets law because this law is for determining the nature of roots of higher degree equations
4 years ago
Arnav Adhiya
15 Points
							
If there are no real zeros, the entire graph is either above the x-axis or below it. Given that the function value at x =1 is negative, the entire function is indeed below the x-axis. Therefore, the function value at x = 0, i.e., c is also below the x-axis and hence c is negative.
9 months ago
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