Given: [a/(b+c)] + [b(a+c)] + [c/(a+b)] = 1 Then What is the Value of :[a2/(b+c)] + [b2(a+c)] + [c2/(a+b)] ?
Hari Eeshwar , 10 Years ago
Grade 11
3 Answers
SHAIK AASIF AHAMED
Last Activity: 10 Years ago
Hello student, Please find the response to your question below I think there is some data missing or some mistake in your question. whether it is b(a+c) or b/a+c also it is b2(a+c) or b2/a+c ? please rechek the question and post it again so that i can provide you with a meaningful answer.
Hari Eeshwar
Last Activity: 10 Years ago
Sir,
Thankyou for the response so that i could post the accurate question as follows:
[a/(b+c)] + [b/(a+c)] + [c/(a+b)] = 1
Then What is the Value of :
[a2/(b+c)] + [b2/(a+c)] + [c2/(a+b)] =?
mycroft holmes
Last Activity: 10 Years ago
We have (a+b+c)[ (a/b+c) + (b/c+a) + (c/a+b) ] = a^2/(b+c)+b^2/(c+a)+c^2/(a+b) + (a+b+c)
Hence if (a/b+c) + (b/c+a) + (c/a+b) =1, the equation becomes