four no.s are in a.p. the sum of the 1 st and las

Question

four no.s are in a.p. the sum of the 1st and last terms is 18 and the product of both the middle terms is 15 . the least no. of the series is.

Samyak Jain · Accepted Answer

Let the 4 numbers in A.P. be a – 3d, a – d, a + d, a + 3d.Given : (a – 3d) + (a + 3d) = 18&(a – d)(a + d) = 15 2a = 18=>a = 9&a2 – d2 = 15=> 92 – d2 = 15=> d2 = 81 – 15 = 66 d = 66When d = 66 ,a – 3d = 9 – 366,a – d = 9 – 66a + d = 9 + 66,a + 3d = 9 + 366.When d = – 66 , a – 3d = 9 + 366,a – d = 9 + 66a + d = 9 – 66,a + 3d = 9 – 366. The AP is either9 – 366 , 9 – 66 , 9 + 66 , 9 + 366or9 + 366 , 9 + 66 , 9 – 66 , 9 – 366 .Thus, the least number of the AP is 9 – 366.

Algebra> four no.s are in a.p. the sum of the 1 st...

four no.s are in a.p. the sum of the 1st and last terms is 18 and the product of both the middle terms is 15 . the least no. of the series is.

suvarna , 6 Years ago

Samyak Jain

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Algebra> four no.s are in a.p. the sum of the 1 st...

four no.s are in a.p. the sum of the 1st and last terms is 18 and the product of both the middle terms is 15 . the least no. of the series is.

suvarna , 6 Years ago

Samyak Jain

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

Ask a Doubt

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