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For what values of p does the vertex of the parabola y=x^2 +2px+13 lie at a distance of 5 units from the origin
6 months ago

Arun
21966 Points

Dear student

it is not clear that distance should be towarda x axis or y axis
it is clear that it is upward parabola

now

its b/2a equals to 5

2p/2 = 5

p = 5
6 months ago
Akash Ranjan
13 Points

Find the vertex ( -p, 13-p^2 ) .
Now using distance formula from origin , equate the distance as 5 .( Distance can be 5 in any direction  so it's totally wrong to assume it's along X or Y axis.

p^2 +(13-p^2)^2 = 25
Solve to get p = 3,-3,4,-4
4 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions