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`        For what values of p does the vertex of the parabola y=x^2 +2px+13 lie at a distance of 5 units from the origin`
one year ago

Arun
24493 Points
```							Dear student it is not clear that distance should be towarda x axis or y axisit is clear that it is upward parabola now its b/2a equals to 5 2p/2 = 5 p = 5
```
one year ago
Akash Ranjan
13 Points
```							Find the vertex ( -p, 13-p^2 ) . Now using distance formula from origin , equate the distance as 5 .( Distance can be 5 in any direction  so it's totally wrong to assume it's along X or Y axis.   p^2 +(13-p^2)^2 = 25 Solve to get p = 3,-3,4,-4
```
one year ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions