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For the function y =x-a/a^2-b^2, and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y =1/a-b
y=x-a/(a+b)(a-b)a-b=x-a/y(a+b)at x=-b , y=-(a+b)/(a+b)(a-b), y=-1/(a-b)sher mohammadb.tech, iit delhi
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