For the function y =[(x-a)/(a^2 -b^2)]
and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .
SEKHAR
12 Years agoGrade 11
1 Answer
bharat bajaj
12 Years ago
y = 1/a-b = x-a / (a+b)(a-b) Hence, 1 = x-1/a+b a+ b = x - 1 Hence, terminal value of x = a+b + 1 Thanks