For the function y =[(x-a)/(a^2 -b^2)]
and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

Question

For the function y =[(x-a)/(a^2 -b^2)] and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

bharat bajaj · Answer

y = 1/a-b = x-a / (a+b)(a-b) Hence, 1 = x-1/a+b a+ b = x - 1 Hence, terminal value of x = a+b + 1 Thanks Bharat Bajaj IIT Delhi askiitians faculty

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For the function y =[(x-a)/(a^2 -b^2)] and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

For the function y =[(x-a)/(a^2 -b^2)]
and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

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For the function y =[(x-a)/(a^2 -b^2)] and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

For the function y =[(x-a)/(a^2 -b^2)] and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .

1 Answers

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For the function y =[(x-a)/(a^2 -b^2)]
and the initial value of the independent variable x0 = a - b. At what terminal value of x the increment ?y = 1/(a-b) .