For any sets A,&B and, using properties of sets prove that : A-(AnB)=A-B;

Question

Arun · Answer

A – (A ∩ B) = A ∩ (A ∩ B)′ (since A – B = A ∩ B′)
= A ∩ (A′ ∪ B′) [by De Morgan’s law)
= (A ∩ A′) ∪ (A ∩ B′) [by distributive law]
= φ ∪ (A ∩ B′)
= A ∩ B′ = A – B

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For any sets A,&B and, using properties of sets prove that : A-(AnB)=A-B;

For any sets A,&B and,
using properties of sets prove that :
A-(AnB)=A-B;

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For any sets A,&B and, using properties of sets prove that : A-(AnB)=A-B;

For any sets A,&B and,using properties of sets prove that :A-(AnB)=A-B;

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For any sets A,&B and,
using properties of sets prove that :
A-(AnB)=A-B;