for any integer n,the argument of z= ( √3+ i ) ^ ( 4n + 1) )/( ( 1- i √3) ) ^ ( 4n )

Question

Shashank Singh · Answer

by converting the above expression in euler form 2^(4n+1) [e^(ipi/6]/ 2^4n [e^(-ipi/3) 2 (e^i(pi/6+pi/3)) = 2e^ipi/2 so the argument is pi/2

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for any integer n,the argument of z= ( √3+ i ) ^ ( 4n + 1) )/( ( 1- i √3) ) ^ ( 4n )

for any integer n,the argument of z= ( √3+ i ) ^ ( 4n + 1) )/( ( 1- i √3) ) ^ ( 4n )

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for any integer n,the argument of z= ( √3+ i ) ^ ( 4n + 1) )/( ( 1- i √3) ) ^ ( 4n )

for any integer n,the argument of z= ( √3+ i ) ^ ( 4n + 1) )/( ( 1- i √3) ) ^ ( 4n )

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