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`        For all complex numbers z1, z2 satisfying |z1|=12 And |z2-3-4i|=5 , then minimum value of lz1-z2l =is .....`
one year ago

Arun
19063 Points
```							Dear student If we analyse it geometrically then,| z1| = 12 meansLocus of all points which has centre at (0,0) and at a distance of 12 units i.e. a circle of radius 12 units. | z2 - 3 - 4i | = 5MeansLocus of points which are at a dostance of 5 units from a fixed point (3,4) Hence minimum value of |z1-z2| = 12 - 10 = 2 units  RegardsArun (askIITians forum expert)
```
one year ago
Pranjal Srivastava
42 Points
```							 |z2-3-4i -z1 +z1|=5for minimum value, 5>|Iz2-z1I – Iz1-3-4iI|therefore, 5>|z1-z2| – |z1| – |3+4i|So, |z1-z2|the minimum value of |z1-z2| is 22.
```
one year ago
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