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Five thieves broke into the jeweler's shop and stole only diamonds. Thief 1 took one half of the first diamond and a diamond Thief 2 took one-half of the rest of the diamond and a diamond. Thie f3 took one-half of the rest of the diamond and a diamond. Thief 4 took one-half of the rest of the diamond and a diamond. Thief 5 didn't have any diamonds left to take. Question: So how many diamonds were there in the jewelry store at first?
Five thieves broke into the jeweler's shop and stole only diamonds.Thief 1 took one half of the first diamond and a diamondThief 2 took one-half of the rest of the diamond and a diamond.Thie f3 took one-half of the rest of the diamond and a diamond.Thief 4 took one-half of the rest of the diamond and a diamond.Thief 5 didn't have any diamonds left to take.Question: So how many diamonds were there in the jewelry store at first?

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9 months ago

## Answers : (1)

2074 Points
```							the lang of ur ques is a bit unclear. however i ll try my best to ans it.let the no. of inital diamonds be A_0.after thief 1 commits his crime, let the no of diamonds LEFT be A_1.similarly after thief 2 commits his crime, let the no of diamonds LEFT be A_2 and so on.....clearly, A_(n+1) = A_n – (A_n/2 + 1)or 2[1 + A_(n+1)] = A_nalso, A_4= 0So, A_3= 2(1+0)= 2so A_2= 2(1+2)= 6so A_1= 2(1+6)= 14or A_0= 2(1+14)= 30Hence there were 30 diamonds initially.KINDLY APPROVE :))
```
9 months ago
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