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find x,y,z real triples satisfying the given conditionx^4+y^4+z^4-4xyz=-1

ashwen venkatesh , 10 Years ago
Grade 12
anser 1 Answers
Amit Jain

Last Activity: 10 Years ago

The whole equation can be re-arranged to (x2-y2)2+(z2-1)2+2(xy-z)2=0

All three squares must be zero. So the triplets can be found out correspondingly as (1,1,1), (-1,1,-1),(1,-1,-1).

Amit Jain
IIT Delhi
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