Grade 12th passAlgebra
Find values of x for which x^3+1=2*(cube root of (2x-1))
Find values of x for which x^3+1=2*(cube root of (2x-1))
1 Answer
Vikas TU
x^3+1=2*(cube root of (2x-1))
cubing both sides
(x^3+1)^3 = 8 (2x – 1)
x^6 + 1 + 3x^6 + 3x^3 = 8(2x – 1)
4x^6 + 3x^3 -16x + 9 = 0
Now make the graph and plot the graph by using wavy curve method,
U will get the approximate roots.
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