Find values of x for which x^3+1=2*( cube root of (2x-1))

Question

Vikas TU · Answer

x^3+1=2*( cube root of (2x-1)) cubing both sides (x^3+1)^3 = 8 (2x – 1) x^6 + 1 + 3x^6 + 3x^3 = 8(2x – 1) 4x^6 + 3x^3 -16x + 9 = 0 Now make the graph and plot the graph by using wavy curve method, U will get the approximate roots.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Find values of x for which x^3+1=2*( cube root of (2x-1))

Find values of x for which x^3+1=2*(cube root of (2x-1))

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Algebra

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship