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find the vaue of x for the equtation [x]^2-5[x]+ 6 <=0

find the vaue of x for the equtation [x]^2-5[x]+ 6 <=0

Grade:10

1 Answers

Rinkoo Gupta
askIITians Faculty 80 Points
7 years ago
([x]-2)([x]-3)<=0
2<=[x]<=3
[x] belong to [2,3]
hence [x]=2,3
hence 2<=x<3 and 3<=x<4
hence 2<=x<4
i.e. x belongs to [2,4)
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty

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