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Find the value of the determinant in the attachment.

Find the value of the determinant in the attachment.

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Grade:12

1 Answers

Arun
25750 Points
3 years ago
Dear student
 
On opening this determinant about 1st row
 
(y+z) [(z+x)(x+y) - zy] + x (zy -xy -y²) + x(yz - z² -xz)
 
 = (y+z) [ x² + xy + yz ] + xyz - x²y - xy² + xyz -xz² -x²z
 
 = y² z + yz² + 3xyz 
 
Hope it helps
 
Thanks and regards

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