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Find the value of the determinant in the attachment.
Dear student On opening this determinant about 1st row (y+z) [(z+x)(x+y) - zy] + x (zy -xy -y²) + x(yz - z² -xz) = (y+z) [ x² + xy + yz ] + xyz - x²y - xy² + xyz -xz² -x²z = y² z + yz² + 3xyz Hope it helps Thanks and regards
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