FIND THE VALUE OF (K) FOR WHICH THERE IS NO SOLUTION OF EQUATIONS
(K+1)X+8Y=4K AND
(K)X+ (K+3)Y=3K-1
Prashant Kumar , 11 Years ago
Grade 12
Algebra> FIND THE VALUE OF (K) FOR WHICH THERE IS ...
1 Answers
bharat bajaj
If there is no solution,
K+1/K = 8/K+3 = 4K/3K-1
K^2 -4K + 3 = 0
K+1/K = 8/K+3 = 4K/3K-1
K^2 -4K + 3 = 0
K = 1,3
6K-2 = k^2 + 3K
K^2 - 3K + 2 = 0
K = 2,1
Hence, K = 1 for no solution
Thanks
6K-2 = k^2 + 3K
K^2 - 3K + 2 = 0
K = 2,1
Hence, K = 1 for no solution
Thanks
Bharat Bajaj
IIT Delhi
IIT Delhi
askiitians faculty
Approved Last Activity: 11 Years ago
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