Find the sum of the series : (12/1)+(12+22/1+2)+(12+22+32/1+2+3)+………upto 31 terms.
Find the sum of the series : (12/1)+(12+22/1+2)+(12+22+32/1+2+3)+………upto 31 terms.
chaman , 12 Years ago
Grade 12
Algebra> progression-and-series...
1 Answers
Pratik Tibrewal
r th term of the series is: SUM(r^2) / SUM(r) where SUM is summation from r = 1 to r
SUM(r^2) = r(r+1)(2r+1)/6
SUM(r) = r(r+1)/2
SUM(r^2)/SUM(r) = (2r+1)/3
we have to find SUM((2r+1)/3) where r varies from 1 to 31
SUM ((2r+1)/3) = 2(n(n+1)/6) + n/3
Put n = 31
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Pratik Tibrewal
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