Aditya Gupta
Last Activity: 4 Years ago
dear student, this is an extremely ez ques.
note that in the condition (z+1)2 =2i if we take Re part both sides, we get
Re((z+1)2= Re(2i)= 0
hence, (z+1)2 =2i itself implies the truth of the 2nd condition Re((z+1)2= 0.
so, we only need to be concerned with solving (z+1)2 =2i
but, we know that 2i= (1+i)^2
so, (z+1)2 = (i+1)^2
or z+1= ± (i+1)
or z= i, – (i+2)
the cardinality of set means the no. of elements in the set, which in this case is clearly 2.
KINDLY APPROVE :))
