Find the remainder when 1! + 2! + 3! + 4! + 5! +.......+ 100! is divided by 24.

4! = 24
and hence for all the terms after 3! will be divisible by 4! and hence by 24

so we just need to check for the forst three terms = 1! + 2! + 3! = 9
and reminder of 9/24 is = 9

Approved