0

Guest

Courses New

Find the real values of x which satisfy X^2-3x+2>0 and x^2-3x-4= or

Find the real values of x which satisfy
X^2-3x+2>0 and x^2-3x-4= or

Grade:11

1 Answers

Susmita
425 Points
5 years ago
Given 
x2-3x-4=0
Or,x2-4x+x-4=0
Or,x(x-4)+1(x-4)=0
Or,(x-4)(x+1)=0
So either x=4 or x=-1.
For x=4,
x2-3x+2=16-12+2=6>0
For x=-1,
x2-3x+2=1+3+2=6>0.
So the values are x=4 and x=-1.
Please approve the answer if you are helped.

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More