MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
Find the RANGE of the function attached in image..................…...
3 months ago

Answers : (1)

Aditya Gupta
823 Points
							
note that 16sin^2x+1 can lie in [1, 17]
also, maximum value of 2 – log2(16sin^2x+1) is 2 – log21=2 – 0=2
also, 16sin^2x+1 can attain value 4 (which lies between 1 and 17), which means that 2 – log2(16sin^2x+1) can attain 0 value.
when it approaches zero, the value of log2^1/2[2 – log2(16sin^2x+1)]= 2log2[2 – log2(16sin^2x+1)] approaches negative infinity
when it attains 2, log2^1/2[2 – log2(16sin^2x+1)]= 2log2[2 – log2(16sin^2x+1)] attains 2
so range is (–infinity, 2].
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details