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        find the radius of the circle which passes through the origin and the points (a,0) and (0,b)
2 years ago

							Dear student let the equation of circle :x2 + y2 + 2gx+ 2fy + c = 0now pass it from (0, 0):c= 0 now pass it from (a, 0)a2 + 2ag = 0g = – a/2 now pass it from (0, b)b2 + 2fb = 0f = – b/2 now radius of circle = (g2 + f2 –c) = (a2 + b2)/4 = ½ (a2 + b2) RegardsArun (askIITians forum expert)

2 years ago
							Let the equation of the circle is x^2+y^2+2gx+2fy+c=0 so if it passes through the origin then c=0, if it passes through (a,0) then a^2+2ga=0 , if passes through (0,b) then b^2+2bf=0  so the equation of circle is x^2+y^2-ax-by=0 so therefore radius of the circle is √(a^2+b^2)/4

2 years ago
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