Find the number of ways in which 5 boys and 5 girls be seated in a row so that all the girls are never together.

Question

noogler · Answer

4!.5!

Meet Singhal · Answer

You can permute the boys in = 5! ways, then you are left with 6 positions to place the girl. Place the girls in 6C5 ways Then permute the girls in 5! ways So your answer is the multiplication of these 3 terms which is = 5! x 6C5 x 5! = 5! x 6! (For a free course on PnC visit dronalectures.com)

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Find the number of ways in which 5 boys and 5 girls be seated in a row so that all the girls are never together.

Find the number of ways in which 5 boys and 5 girls be seated in a row so that all the girls are never together.

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Find the number of ways in which 5 boys and 5 girls be seated in a row so that all the girls are never together.

Find the number of ways in which 5 boys and 5 girls be seated in a row so that all the girls are never together.

2 Answers

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Other Related Questions on Algebra

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