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find the nth term and the sum of n terms of the series 6+9+21+69+261+
The gp has been formed in the question, so the general term is as follows- Tr= ar+b+c.4^(r-1), T1=6 ,T2=9, T3=21 so by this equations a=0,b=5,c=1. So put the value in the original equation and get the general term as 5+4^(r-1) so the sum to n terms is 5n+ [(4^(n-1))/3]
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