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`        Find the no. Of ways in which 3 distinct nos. Can be selected from the set{1,2,3...99,100} so that they form an AP `
4 months ago

Vishrut Arora
9 Points
```							This question can be easily solved by identifying the seriesconsider,AP with common difference of 11,2,3,....2,3,4.....finally 98,99,100=> There are 98 APs possible with common difference of 1 AP with common difference of 21,3,5..2,4,6...finally 96,98,100=> There are 96 APs possible with common difference of 2and so on till AP with common difference of 49 1,50,99....2,51,100....=> There are 2 APs with the maximum common difference possible Now for total no.of APs u have to add 98+96+94+....2using the formula n/2(2*a+(n-1)*d) We finally get the answer as 2450
```
2 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions