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f(x) =x²-x+1/x²+x+1 = (x²+x+1- 2x )/x²+x+1Hence, f(x) = 1 - 2x/x²+x+1df(x)/dx = 0x = 1, -1Now find the value of d/dx(df(x)/dx) at x = 1,-1For x = +1, it is positive. Hence there is a minima at x = +1.Therefore Minimum value of f(x) is at x=+1 which is f(+1) = 1/3
Thanks & RegardsBharat Bajaj,askIITians FacultyQualification.IIT Delhi
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