find the minimum value of f(x) = (x²-x+1)÷(x²+x+1)

so for minimum , put first derivative = 0
so we will get x =+1

so maximum value of f(x) = 3 , at x= -1
and minimum value will be at x= 1, f(x) = 1/3


Thanks,
Ruchi
Askiitian's Faculty