df/dx=(x+1)^3.2(x-3)+(x-3)^2.3(x+1)^2
=(x+1)^2(x-3)[2(x+1)+3(x-3)]
=(x-3)[2x+2+3x-9]
=(x-3)(5x-7)
for function to be increasing df/dx>or=0
(x-3)(5x-7)>or =0
x<or=7/5 or x>or=3
i.e. (-infinity,7/5]U[3,infinity)
for function to be decreasing df/dx<0
(x-3)(5x-7)<0
7/5<x<3
Thanks & Regards
Rinkoo Gupta
AskIItians Faculty