Grade Upto college level Algebra

Find the intervals in which f(x) = logcosx is strictly decreasing and strictly increasing.

Manvendra Singh chahar

12 Years agoGrade Upto college level

1 Answer

Jitender Singh

12 Years ago

Ans:

$f(x) = \log (cos(x))$

$f^{'}(x) = \frac{-sinx}{cosx} = -tanx$

f(x) is increasing in the interval where

$-tanx> 0$

$tanx< 0$

$(n-\frac{1}{2})\pi < x< n\pi$

f(x) is decreasing in the interval where

$tanx>0$

$n\pi< x< (n+\frac{1}{2})\pi$

Thanks & Regards

Jitender Singh

IIT Delhi

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Find the intervals in which f(x) = logcosx is strictly decreasing and strictly increasing.

Manvendra Singh chahar

1 Answer

Jitender Singh

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