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Find the integral values of a for which (A + 2) X square + 2(a + 1)X + a = 0 will have both roots integer
Dear Chitresh x = – 2(a+1) ± sqrt (4a^2 + 4 + 8a – 4a^2 – 8a) / 2(a+2) x = – 2(a+1) ± 2 / 2a + 4 x = – 2a – 4 / 2a + 4 or x = – 2a / 2a + 4 x = – 1 or x = -a / a + 2 now you can find out condition for a easily
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