0

Guest

Courses New

Find the equation of the plane passing through the point (–1, 3, 2) and perpen- dicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + z = 0

Find the equation of the plane passing through the point (–1, 3, 2) and perpen- dicular to each of the planes x + 2y + 3z = 5 and 3x + 3y + z = 0

Grade:Upto college level

1 Answers

SHAIK AASIF AHAMED
askIITians Faculty 74 Points
9 years ago
equation of a plane passing through (-1,3,2) is
a(x+1)+b(y-3)+c(z-2)=0
since the plane is perpendicular to given 2 planes
a+2b+3c=0;
9a+9b+3c=0
by solving we get
\frac{a}{6-18}=\frac{b}{3-27}=\frac{c}{9-18}
\frac{a}{4}=\frac{b}{8}=\frac{c}{3}
the equation of plane is 4(x+1)+8(y-3)+3(z-2)=0
4x+8y+3z-26=0
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More