Arun
Last Activity: 8 Years ago
olving the equations 3x + 2y + 6 = 0 and 2x – 5y + 4 = 0 we get x = –2 and y = 0.
Solving the equations x – 3y – 6 = 0 and 2x – 5y + 4 = 0 we get x = –42 and y = –16.
Solving the equations 3x + 2y + 6 = 0 and x – 3y – 6 = 0 we get x = –6/11 and y = –24/11.
So let the intersection points be A, B and C i.e. the triangle be ABC.
Coordinates of A, B and C will be A(-2, 0); B(-42, -16) and C(-6/11, -24/11).
By mid-point formula the mid-point of AB will be (-22, -8)
Equation of line passing through this mid-point and the opposite vertex C(-6/11, -24/11) will be the equation of the median from C. The equation will be
16x - 59y -120 = 0. (From two point form)
Similarily find the equations of median through A & B
