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Find the equation of the median of a triangle whose sides are given by the equations 3x+2y+6=0,2x-5y+4=0,x-3y-6=0
olving the equations 3x + 2y + 6 = 0 and 2x – 5y + 4 = 0 we get x = –2 and y = 0.Solving the equations x – 3y – 6 = 0 and 2x – 5y + 4 = 0 we get x = –42 and y = –16.Solving the equations 3x + 2y + 6 = 0 and x – 3y – 6 = 0 we get x = –6/11 and y = –24/11.So let the intersection points be A, B and C i.e. the triangle be ABC.Coordinates of A, B and C will be A(-2, 0); B(-42, -16) and C(-6/11, -24/11).By mid-point formula the mid-point of AB will be (-22, -8)Equation of line passing through this mid-point and the opposite vertex C(-6/11, -24/11) will be the equation of the median from C. The equation will be 16x - 59y -120 = 0. (From two point form) Similarily find the equations of median through A & B
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