find the equation of the circle passing through the origin and cutting the cirles x^2+y^2-4x+6y+10=0 and x^2+y^2+12y+6=0 at right angles

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Arun · Answer

Dear Dhruv Use equation (S1 + k S2) = 0 Then Answer will be as follows- 2 (x² +y²) - 7x +2y = 0 Regards Arun (askIITians forum expert)

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find the equation of the circle passing through the origin and cutting the cirles x^2+y^2-4x+6y+10=0 and x^2+y^2+12y+6=0 at right angles

find the equation of the circle passing through the origin and cutting the cirles x^2+y^2-4x+6y+10=0 and x^2+y^2+12y+6=0 at right angles

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find the equation of the circle passing through the origin and cutting the cirles x^2+y^2-4x+6y+10=0 and x^2+y^2+12y+6=0 at right angles

find the equation of the circle passing through the origin and cutting the cirles x^2+y^2-4x+6y+10=0 and x^2+y^2+12y+6=0 at right angles

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Other Related Questions on Algebra

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