Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        find the equation of the circle for which the line segment joining the points(8,0) and (0,-3) is a diameter `
2 years ago

Meet
137 Points
```							It means these points are the diametric ends of the circle so the equation of the circle is (x-8)(x-0) + (y-0)(y+3)=0 and it is x^2+y^2-8x+3y=0
```
2 years ago
Arun
23346 Points
```							If we are given with diameter coordinates (x1, y1) & (x2, y2) then equation of circle :(x –x1) (x –x2) + (y – y1)(y – y2) = 0similarly(x –8)(x – 0) + (y – 0)(y + 3) = 0now you can simplify RegardsArun (askIITians forum expert)
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions